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3x^2+6x^2=135
We move all terms to the left:
3x^2+6x^2-(135)=0
We add all the numbers together, and all the variables
9x^2-135=0
a = 9; b = 0; c = -135;
Δ = b2-4ac
Δ = 02-4·9·(-135)
Δ = 4860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4860}=\sqrt{324*15}=\sqrt{324}*\sqrt{15}=18\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{15}}{2*9}=\frac{0-18\sqrt{15}}{18} =-\frac{18\sqrt{15}}{18} =-\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{15}}{2*9}=\frac{0+18\sqrt{15}}{18} =\frac{18\sqrt{15}}{18} =\sqrt{15} $
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